Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
- A single node tree is a BST
An example:
2
/ \
1 4
/ \
3 5
The above binary tree is serialized as {2,1,4,#,#,3,5}
(in
level order).
/**
* Definition of TreeNode:
* public class TreeNode {
* public int val;
* public TreeNode left, right;
* public TreeNode(int val) {
* this.val = val;
* this.left = this.right = null;
* }
* }
*/
public class Solution {
/**
* @param root: The root of binary tree.
* @return: True if the binary tree is BST, or false
*/
public boolean isValidBST(TreeNode root) {
return helper(root, Integer.MIN_VALUE, Integer.MAX_VALUE);
}
boolean helper(TreeNode root, int minLimit, int maxLimit) {
if(root == null) return true;
if((minLimit != Integer.MIN_VALUE ? root.val > minLimit : true) &&
(maxLimit != Integer.MAX_VALUE ? root.val < maxLimit : true) &&
helper(root.left, minLimit, root.val)
&& helper(root.right, root.val, maxLimit))
return true;
else
return false;
}
}