Given a matrix
, and a target
, return the number of non-empty submatrices that sum to target.
A submatrix x1, y1, x2, y2
is the set of all cells matrix[x][y]
with x1 <= x <= x2
and y1 <= y <= y2
.
Two submatrices (x1, y1, x2, y2)
and (x1', y1', x2', y2')
are different if they have some coordinate that is different: for example, if x1 != x1'
.
Example 1:
Input: matrix = [[0,1,0],[1,1,1],[0,1,0]], target = 0
Output: 4
Explanation: The four 1x1 submatrices that only contain 0.
Example 2:
Input: matrix = [[1,-1],[-1,1]], target = 0
Output: 5
Explanation: The two 1x2 submatrices, plus the two 2x1 submatrices, plus the 2x2 submatrix.
Note:
1 <= matrix.length <= 300
1 <= matrix[0].length <= 300
-1000 <= matrix[i] <= 1000
-10^8 <= target <= 10^8
解題思路:
class Solution {
public:
int numSubmatrixSumTarget(vector<vector<int>>& matrix, int target)
{
int rows = matrix.size() , cols = matrix[0].size() ;
vector<vector<int>> prev_sum(rows , vector<int>(cols , 0)) ;
int res = 0 ;
for(int row = 0 ; row < rows ; row++)
for(int col = 0 ; col < cols ; col++)
{
if(col == 0) prev_sum[row][col] = matrix[row][col] ;
else prev_sum[row][col] = prev_sum[row][col - 1] + matrix[row][col] ;
}
for(int begin_row = 0 ; begin_row < rows ; begin_row++)
{
vector<int> row_sum(cols , 0) ;
for(int end_row = begin_row ; end_row < rows ; end_row++)
{
unordered_map<int , int> prev_col_sum ;
for(int col = 0 ; col < cols ; col++)
{
row_sum[col] += prev_sum[end_row][col] ;
if(row_sum[col] == target) res++ ;
if( !prev_col_sum.empty() && prev_col_sum.count(row_sum[col] - target)) res += prev_col_sum[row_sum[col] - target] ;
prev_col_sum[row_sum[col]]++ ;
}
}
}
return res ;
}
};