動態規劃函數
#include<iostream>
using namespace std;
int main()
{
int n, C, i, j;
cout << "請輸入揹包容量:";
cin >> C;
cout << "請輸入物品數:";
cin >> n;
int *w = new int[n+1];
int *v = new int[n+1];
int *x = new int[n+1];
int **V = new int*[n+1];//設立動態數組,節省空間
for (i = 0; i < n + 1; i++)
{
V[i] = new int[C + 1];
}
cout << "請輸入這些物品的重量:";
w[0] = 0;
for (i = 1; i < n + 1; i++)//重量和價值都從下標1開始存,這樣方便後面計算
cin >> w[i];
cout << "請輸入這些物品的價值:";
v[0] = 0;
for (i = 1; i < n + 1; i++)
cin >> v[i];
for (i = 0; i < n + 1; i++)//初始化第0列
V[i][0] = 0;
for (j = 0; j < C + 1; j++)//初始化第0行
V[0][j] = 0;
for (i = 1; i <= n; i++)
for (j = 1; j <= C; j++)
{
if (j < w[i])
V[i][j] = V[i - 1][j];
else
V[i][j] = V[i - 1][j] > (V[i - 1][j - w[i]] + v[i]) ? V[i - 1][j] : (V[i - 1][j - w[i]] + v[i]);
}
for (j = C, i = n; i > 0; i--)
{
if (V[i][j] > V[i - 1][j])
{
x[i] = 1;
j = j - w[i];
}
else
x[i] = 0;
}
/*控制X的輸出格式*/
cout << "此題最優解爲:X={";
for (i = 1; i < n; i++)
cout << x[i] << ",";
cout << x[i] << "}" << endl;
/*輸出表*/
/*控制表頭的輸出格式*/
cout << '\t';
for (j = 0; j < C+1; j++)
cout << j << '\t';
cout << endl;
/*輸出表最左邊一列和表的內容*/
for (i = 0; i < n + 1; i++)
{
cout << i << '\t';//輸出表最左邊
for (j = 0; j < C + 1; j++)//輸出表的內容
cout << V[i][j] << '\t';
cout << endl;
}
delete[] w;
delete[] v;
delete[] x;
delete[] V;
return 0;
}