問題
Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
For example, given array S = {-1 2 1 -4}, and target = 1.
The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
分析:
找出與給出的target最接近的三個數的和。類似於3Sum,也是先排序後遍歷配合左右遊標[O(N^2)],使用abs函數判斷當前解和最優解與target的距離來對最優解進行調整,對於遊標的移動,如果和小於target則左遊標右移,大於則右遊標左移。
Java
class Solution {
public int threeSumClosest(int[] nums, int target) {
Arrays.sort(nums);
int ans = nums[0] + nums[1] + nums[2];
for(int i = 0; i < nums.length; i++){
int temp = target - nums[i];
int j = i + 1, k = nums.length - 1;
while(j < k){
if(Math.abs(target - ans) > Math.abs(temp - nums[j] - nums[k])){
ans = nums[i] + nums[j] + nums[k];
if( ans == target) return target;
}
if(temp - nums[j] - nums[k] < 0)
k--;
else
j++;
}
}
return ans;
}
}