初學tensorflow，如果不對請指正，謝謝
tenorflow中有一個函數叫reshape()函數,這個函數可以將輸入的tensor變換成shape的格式。具體看函數說明：
def reshape(tensor, shape, name=None):
Reshapes a tensor.
Given `tensor`, this operation returns a tensor that has the same values
as `tensor` with shape `shape`.
If one component of `shape` is the special value -1, the size of that dimension
is computed so that the total size remains constant. In particular, a `shape`
of `[-1]` flattens into 1-D. At most one component of `shape` can be -1.
If `shape` is 1-D or higher, then the operation returns a tensor with shape
`shape` filled with the values of `tensor`. In this case, the number of elements
implied by `shape` must be the same as the number of elements in `tensor`.1.給定一個tensor，怎麼確定它的shape。
2.給定一個tensor和shape，經過reshape(tensor,shape)變換後返回的tensor是什麼格式的。
先看一看文檔中給出的例子：
For example:
```prettyprint
# tensor 't' is [1, 2, 3, 4, 5, 6, 7, 8, 9]
# tensor 't' has shape [9]
reshape(t, [3, 3]) ==> [[1, 2, 3],
[4, 5, 6],
[7, 8, 9]]
# tensor 't' is [[[1, 1], [2, 2]],
# [[3, 3], [4, 4]]]
# tensor 't' has shape [2, 2, 2]
reshape(t, [2, 4]) ==> [[1, 1, 2, 2],
[3, 3, 4, 4]]
# tensor 't' is [[[1, 1, 1],
# [2, 2, 2]],
# [[3, 3, 3],
# [4, 4, 4]],
# [[5, 5, 5],
# [6, 6, 6]]]
# tensor 't' has shape [3, 2, 3]首先，tensor的維數與shape中元素的個數是相等的；其次，shape中數字的乘積與tensor中元素的個數相等，因此在調用reshape()函數時應注意元素個數保持一致。要確定給定的tensor的shape，應該從外往裏看。例如
# tensor 't' is [[[1, 1], [2, 2]],
# [[3, 3], [4, 4]]]
# tensor 't' has shape [2, 2, 2]
reshape(t, [2, 4]) ==> [[1, 1, 2, 2],
[3, 3, 4, 4]]經過reshape變化的t，最外層包含兩個元素，裏面一層包含4個元素，相當於2維數組。變化之前的t,最外層包含兩個元素（第一行末尾一個逗號隔開），中間層每層兩個元素（第一行中間一個逗號隔開），最內層兩個元素，相當於三維數組。
給定了tensor和shape後，將tensor按一維展開，再按照給定的shape重新組合。
如果shape中有-1,函數會自動計算維度，但只能有有個-1.