PTA甲級——1002 A+B for Polynomials (25 分)

1002 A+B for Polynomials (25 分)

This time, you are supposed to find A+B where A and B are two polynomials.

Input Specification:

Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial:

K N​1​​ a​N​1​​​​ N​2​​ a​N​2​​​​ ... N​K​​ a​N​K​​​​

where K is the number of nonzero terms in the polynomial, N​i​​ and a​N​i​​​​ (i=1,2,⋯,K) are the exponents and coefficients, respectively. It is given that 1≤K≤10，0≤N​K​​<⋯<N​2​​<N​1​​≤1000.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.

Sample Input:

2 1 2.4 0 3.2
2 2 1.5 1 0.5

Sample Output:

3 2 1.5 1 2.9 0 3.2

#include<iostream>
#include<cmath>
#include<cstdio>
#include<iomanip>
#include<stdlib.h>
using namespace std;
int main()
{
    int k,a,num=0;
    double b,N[1001]={0};
    for(int i=0;i<2;i++)
    {
        scanf("%d",&k);
        while(k--)
        {
            scanf("%d%lf",&a,&b);
            N[a]+=b;
        }
    }
    for(int i=0;i<1001;i++)
        if(N[i])num++;
    printf("%d",num);
    for(int i=1000;i>=0;i--)
        if(N[i])printf(" %d %.1f",i,N[i]);
    return 0;
}