把數轉換成length位的二進制字符串

#include<iostream>
#include<stdlib.h>
using namespace std;

template<typename T>
string binaryFormat(T val, int length){ //要轉換成length位的二進制字符串
    string binaryStr(length, '0');
    for(int i = 0; i < length; i++){
        if((val >> i) & 1)
            binaryStr[length - 1 - i] = '1';
    }

    return binaryStr; //返回值是一個字符串
}
/*
template <typename T>
string formatBinary(T val)
{
    int length = 8 ;//  要轉換成多少位二進制字符串
    string binaryFormat(length, '0');
    for (int i = 0; i < length; i++)
    {
        if ((val >> i) & 1)
            binaryFormat[length - 1 - i] = '1';
    }

    return binaryFormat;
}
*/

int main(){
    for(int i = 0; i < 17; i++){
        cout<<binaryFormat(i, 8)<<endl;
    }
    cout<<endl;
    cout<<binaryFormat(250, 8)<<endl;
    cout<<binaryFormat(251, 8)<<endl;
    cout<<binaryFormat(252, 8)<<endl;
    cout<<binaryFormat(253, 8)<<endl;
    cout<<binaryFormat(254, 8)<<endl;
    cout<<binaryFormat(255, 16)<<endl;


    return 0;
}