[leetcode] 【字符串】58. Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5.

 

題意

一個字符串裏最後一個單詞的長度

題解

遍歷字符串，計算每個單詞的長度，返回最後一個單詞長度就行。注意細節即可

 

class Solution {
public:
    int lengthOfLastWord(string s) {
        if(s.size()==0)
            return 0;
        int n=0;
        int cur_n=0;
        for(int i=0;i!=s.size();i++)
        {
            if(s[i]!=' ')
                cur_n++;
            else 
            {
                if(cur_n!=0)
                    n=cur_n;
                cur_n=0;
            }
                
        }
        if(cur_n!=0)
            n=cur_n;
        return n;
    }
};