LeetCode 合併兩個有序鏈表(非遞歸)

# Leetcode 合併兩個有序鏈表
# 非遞歸方法
# 我使用了較爲笨的一種方法來接 先提取所有數到數組--->排序--->有了順序錶轉換爲鏈表就方便了
# 考慮到鏈表的特殊性質，我把他們一個個先實例化爲一個個僅僅含有val，next都是None的鏈表，然後從後往前一個一個的鏈接上就行了

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None

class Solution:
    def mergeTwoLists(self, l1, l2):
        if l1 == None and l2 == None:
            return None
        elif l1 == None and l2 != None:
            return l2
        elif l1 != None and l1 == None:
            return l1
        else:
            l1_ = []
            while l1 is not None:
                l1_.append(l1.val)
                l1 = l1.next
            l2_ = []
            while l2 is not None:
                l2_.append(l2.val)
                l2 = l2.next

            final = l1_ + l2_
            final = sorted(final)

            # list2ListNode
            each_node = []
            for ele in final:
                each_node.append(ListNode(ele))

            length = len(each_node) - 1
            i = 0
            while i != length:
                each_node[length - i - 1].next = each_node[length - i]
                i += 1

            return each_node[0]