題目描述
Assume you are an awesome parent and want to give your children some cookies. But, you should give each child at most one cookie. Each child i has a greed factor gi, which is the minimum size of a cookie that the child will be content with; and each cookie j has a size sj. If sj >= gi, we can assign the cookie j to the child i, and the child i will be content. Your goal is to maximize the number of your content children and output the maximum number.
Note:
You may assume the greed factor is always positive.
You cannot assign more than one cookie to one child.
Example 1:
Input: [1,2,3], [1,1] Output: 1 Explanation: You have 3 children and 2 cookies. The greed factors of 3 children are 1, 2, 3. And even though you have 2 cookies, since their size is both 1, you could only make the child whose greed factor is 1 content. You need to output 1.
比較兩個數組,當餅乾數組的某個元素>= 孩子需要的,就可以分給小孩
解題思路
給兩個數組排序,設置計數器,遍歷兩個數組,判斷是否能分給餅乾,能的話,計數器+1
代碼如下
class Solution {
public:
int findContentChildren(vector<int>& g, vector<int>& s) {
sort(g.begin(), g.end());
sort(s.begin(), s.end());
int p = 0;
int count = 0;
for(int i = 0; i < g.size(); i++){
int j = p;
for(j; j < s.size(); j++){
if(s[j] >= g[i]){
p = j + 1;
count++;
break;
}
}
}
return count;
}
};