有一段文本，將文本中的所有單詞，存放到一個字符指針數組中（要求每個單詞內存恰好）。
第一種做法
char c[] = " asd afil kjgl rip kjgdr gds sdg gs ";
char b[10] = {0};
char *a[10] = {NULL};
int i = 0, j = 0,k = 0; //i使字符不斷後移,j用來標識指針a,k用來標識中間字符數組b;
while (1) {//把字符串的'\0' 作爲if判斷的條件,避免遇到\0不在判斷
if (c[i] != ' ' && c[i] != '\0') {
b[k++] = c[i++];
continue; //提高效率,當進行此if判斷時,就不在進行一下if判斷
}
if ((c[i] == ' ' || c[i] == '\0') && k != 0) {
//k判斷是否有字符賦給b數組,沒有的話意味着前面是空空格,就不在需要進行判斷,提高運行效率
b[k] = '\0'; //給數組b加上\0 ,結束字符
a[j] = malloc(strlen(b) + 1); //爲指針開闢空間
strcpy(a[j], b); //b是首地址,a[j]也是首地址,函數具有複製功能,如:%s
k = 0;
j++;
}
if (c[i] == '\0') { //把while中的\0判斷移到可以先判斷\0的情況
break;
}
i++;
}
for (int i = 0 ; i < j ; i++ ) {
printf("%s\n", a[i]); //int a = 10; int *b = null; b = &a; *b = 10;
free(a[i]); //* 具有指向功能,
a[i] = NULL;
}
char str[] = " a41 a1421 b3511 b b c c c c dddddd jkthku";
//2.如何存儲一個單詞?
char tempStr[20] = {0}; //存儲文本中的一個單詞
//3.如何存儲堆區空間的地址?
char *p[255] = {0};
//4.如何查找單詞,並且將對應的單詞存放到臨時數組中?
int i = 0; //標識str字符串中字符的下標
int j = 0; //標識tempStr字符串中字符的下標
int k = 0; //標識指針數組中元素的下標.
while (1) {
if (str[i] != ' ' && str[i] != '\0') {
//當獲取到的元素不爲空格時,將它存儲到臨時數組tempStr中.
tempStr[j++] = str[i];
} else if (j != 0) {
//當遇到空格,或者遇到\0時.單詞的存放結束
tempStr[j] = '\0'; //最後一個元素補上\0
//動態計算所需堆區空間的大小,將地址存放到對應的字符指針數組元素中
p[k] = malloc(strlen(tempStr) + 1);
//將臨時數組tempStr中字符串拷貝到對應堆區空間上.
strcpy(p[k], tempStr);
k++;
j = 0; //存儲下一單詞時,又從數組的第一個字符開始.
}
//當讀取到\0時,字符串讀取完畢,跳出循環
if (str[i] == '\0') {
break;
}
i++; //移動到str數組中的下一個元素
}
for (int i = 0; i < k; i++) {
printf("%s ", p[i]);
free(p[i]);
p[i] = NULL;
}
char str[50] =" qwo shi shui nishi hhdj";
char temp[20] = {0};
char *p[10] = {0};
int count = 0;
int d = 0,i = 0,index = 0,h = 0;
while (str[i] != '\0') {
if (str[i] != ' ') {
count ++;
i ++;
index = i - count;
}
if (str[i] == ' ' || str[i] == '\0' ){
if (count != 0) {
int k = 0;
for (int j = index; j < i;j ++) {
temp[k] = str[j];
k ++;
d = k;
}
temp[k] = '\0';
printf("%s\n",temp);
p[h] = malloc(count + 1);
strcpy(p[h], temp);
h ++;
count = 0;
}
i ++;
}
}
for (int i = 0; i < h; i ++) {
printf("%s ",p[i]);
free(p[i]);
p[i] = NULL;
}
char a[] = " The end of the World Cup does not mean the end of international competition in Brazil this year";
char *p[100] = {0}; //記錄單詞
char temp[100] = {0}; //臨時記錄單詞
int i = 0; //記錄a[]數組元素的位置
int j = 0; //記錄單詞的個數
int k = 0; //記錄temp[]數組中臨時單詞的字母個數(元素位置)
int count = 0;
while (a[i] != '\0') {
if ((a[i] >= 'a' && a[i] <= 'z') || (a[i] >= 'A' && a[i] <= 'Z')) {
count++;
temp[k] = a[i];
k++;
} else if (k != 0) {
temp[k] = '\0';
k = 0;
p[j] = malloc(sizeof(char) * count + 1);
strcpy(p[j], temp);
printf("%s ", p[j]);
free(p[j]);
p[j] = NULL;
j++;
count = 0;
}
if (a[i + 1] == '\0' && a[i] != ' ') {
temp[k] = '\0';
k = 0;
p[j] = malloc(sizeof(char) * count + 1);
strcpy(p[j], temp);
printf("%s ", p[j]);
free(p[j]);
p[j] = NULL;
}
i++;
}
over