題目鏈接:https://leetcode-cn.com/problems/minimum-size-subarray-sum/
思路:雙指針
首先兩個指針同時指向0位,beg,last
如果當前值之和大於等於s,則l循環減去nums[beg],beg++
然後加上nums[last],last++
class Solution {
public:
int minSubArrayLen(int s, vector<int>& nums) {
int len=nums.size();
int beg=0,last=0;
int result_min_len=INT_MAX;
int ans=0;
while(last<len)
{
ans+=nums[last];
while(ans>=s)
{
result_min_len=min(result_min_len,last-beg+1);
ans-=nums[beg];
beg++;
cout<<beg<<" "<<last<<" "<<ans<<endl;
}
// cout<<ans<<endl;
last++;
}
return result_min_len==INT_MAX?0:result_min_len;
}
};