1281.整數的各位積和之差
題目描述:
給你一個整數 n,請你幫忙計算並返回該整數「各位數字之積」與「各位數字之和」的差。
示例 1:
輸入:n = 234
輸出:15
解釋:
各位數之積 = 2 * 3 * 4 = 24
各位數之和 = 2 + 3 + 4 = 9
結果 = 24 - 9 = 15
示例 2:
輸入:n = 4421
輸出:21
解釋:
各位數之積 = 4 * 4 * 2 * 1 = 32
各位數之和 = 4 + 4 + 2 + 1 = 11
結果 = 32 - 11 = 21
提示:
1 <= n <= 10^5
題解1:
輸的範圍爲1~100000,計算每一位的值求和與積,最後求積和之差
class Solution {
public int subtractProductAndSum(int n) {
//計算每一位上的數字
int shiwan = n/100000;
int wan = n%100000/10000;
int qian = n%10000/1000;
int bai = n%1000/100;
int shi = n%100/10;
int ge = n%10;
//求和
int sum = shiwan+wan+qian+bai+shi+ge;
//求積
int ji = 1;
if(shiwan!=0){
ji = shiwan*wan*qian*bai*shi*ge;
}else if(wan!=0){
ji = wan*qian*bai*shi*ge;
}else if(qian!=0){
ji = qian*bai*shi*ge;
}else if(bai!=0){
ji = bai*shi*ge;
}else if(shi!=0){
ji = shi*ge;
}else{
ji = ge;
}
//返回差值
return ji-sum;
}
}
題解1改進:
利用循環改進題解1
class Solution {
public int subtractProductAndSum(int n) {
int ji = 1;
int sum = 0;
while(n!=0){
ji *=n%10;
sum +=n%10;
n/=10;
}
return ji-sum;
}
}