PAT 1083 List Grades（25 分)（排序）

Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:

Each input file contains one test case. Each case is given in the following format:

N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
... ...
name[N] ID[N] grade[N]
grade1 grade2

where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade's interval. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student's name and ID, separated by one space. If there is no student's grade in that interval, output NONE instead.

Sample Input 1:

4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100

Sample Output 1:

Mike CS991301
Mary EE990830
Joe Math990112

Sample Input 2:

2
Jean AA980920 60
Ann CS01 80
90 95

Sample Output 2:

NONE

題意：最後一行輸入給出範圍，如果不存在這範圍的學生，輸出NONE

代碼：

#include<bits/stdc++.h>
using namespace std;
struct student
{
    char name[11];
    char id[11];
    int grade;
} stu[100];

bool cmp(student a,student b)
{
    return a.grade>b.grade;
}

int main()
{
    int n;
    scanf("%d",&n);
    for(int i=0; i<n; i++)
    {
        scanf("%s %s %d",stu[i].name,stu[i].id,&stu[i].grade);
    }
    int left,right;
    scanf("%d%d",&left,&right);
    sort(stu,stu+n,cmp);
    bool flag=false;
    for(int i=0; i<n; i++)
    {
        if(stu[i].grade>=left&&stu[i].grade<=right)
        {
            printf("%s %s\n",stu[i].name,stu[i].id);
            flag=true;
        }
    }
    if(flag==false)
        printf("NONE\n");
    return 0;
}