題目
一隻青蛙一次可以跳上1級臺階,也可以跳上2級。求該青蛙跳上一個n級的臺階總共有多少種跳法。運行時顯示超時源代碼
#include<iostream>
using namespace std;
int cnt = 0;
int jumpFloor(int number){
if (number == 1)jumpFloor(number - 1);
if (number == 0)cnt++;
if (number >=2){
jumpFloor(number - 1);
jumpFloor(number - 2);
}
return cnt;//這道題用遞歸時會超時
}
int main(){
int number,t;
cin >> number;
if (number == 0)t = 0;
else t=jumpFloor(number);
cout << t << endl;
return 0;
}
- AC的代碼
class Solution {
public:
int jumpFloor(int number) {
if (number == 0 || number == 1) return number;
int a = 1, b = 2;
while (number-->1){
b= a + b;
a = b - a;
}
return a;//總結規律後發現原來考的是斐波那挈數列
}
};