题目描述
输入一棵二叉树,求该树的深度。从根结点到叶结点依次经过的结点(含根、叶结点)形成树的一条路径,最长路径的长度为树的深度。
思路:层次遍历,直接遍历每一层,左右节点不为空d就加1。
python
# -*- coding:utf-8 -*-
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def TreeDepth(self, pRoot):
# write code here
if not pRoot:
return 0
a = [pRoot]
d = 0
while a :
b = []
for node in a:
if node.left:
b.append(node.left)
if node.right:
b.append(node.right)
a = b
d = d + 1
return d
c++的代码实现给递归方法
c++
/*
struct TreeNode {
int val;
struct TreeNode *left;
struct TreeNode *right;
TreeNode(int x) :
val(x), left(NULL), right(NULL) {
}
};*/
class Solution {
public:
int TreeDepth(TreeNode* pRoot)
{
if(pRoot==NULL)
return 0;
return max(TreeDepth(pRoot->left),TreeDepth(pRoot->right))+1;
}
};