在開發微信小遊戲中,要將遊戲遊戲UI中的摸個按鈕映射到屏幕上(計算出按鈕在屏幕的rect)。
https://developers.weixin.qq.com/minigame/dev/api/open-api/user-info/wx.createUserInfoButton.html
wx.createUserInfoButton(Object object); 中 style 參數 left|top|width|heigth 如何獲取。
將遊戲UI中按鈕映射到手機屏幕中,獲取對應屏幕座標。參考如下代碼:
/**
* 將按鈕映射到手機屏幕,獲取到屏幕 rect
* @param btn 需要被映射的按鈕
* @param caNode 父節點(在cocos 裏面設置的 Canvas 寬高的父節點。)
*/
public static GetBtnRankRect(btn: cc.Node, caNode: cc.Node) {
// wx.getSystemInfo 的同步版本
let sys = window["wx"].getSystemInfoSync();
let rect = btn.getBoundingBoxToWorld();
let ratio = cc.view.getDevicePixelRatio();
let scale = cc.view.getScaleX();
let factor = scale / ratio;
let diffY = caNode.height - cc.view.getDesignResolutionSize().height;
let left = rect.x * factor;
let top = sys.screenHeight - (rect.y + rect.height) * factor - diffY / 2 * factor;
let w = rect.width * factor;
let h = rect.height * factor;
// 手機屏幕 的區域 rect
let srect = { left: left, top: top, w: w, h: h };
return srect;
}