CodeForces 349B Color the Fence （貪心）

B. Color the Fence

time limit per test:2 seconds

memory limit per test:256 megabytes

input:standard input

output:standard output

Igor has fallen in love with Tanya. Now Igor wants to show his feelings and write a number on the fence opposite to Tanya's house. Igor thinks that the larger the number is, the more chance to win Tanya's heart he has.

Unfortunately, Igor could only get v liters of paint. He did the math and concluded that digitd requires a_d liters of paint. Besides, Igor heard that Tanya doesn't like zeroes. That's why Igor won't use them in his number.

Help Igor find the maximum number he can write on the fence.

Input

The first line contains a positive integer v(0 ≤ v ≤ 10⁶). The second line contains nine positive integersa₁, a₂, ..., a₉(1 ≤ a_i ≤ 10⁵).

Output

Print the maximum number Igor can write on the fence. If he has too little paint for any digit (so, he cannot write anything), print -1.

Sample test(s)

Input

5
5 4 3 2 1 2 3 4 5

Output

55555

Input

2
9 11 1 12 5 8 9 10 6

Output

33

Input

0
1 1 1 1 1 1 1 1 1

Output

-1

題意：

在牆上用一定量的油漆塗數字，儘量使塗出來的數字大。

輸入：

1.擁有油漆量

2.每個數字所需顏料量

思路：

一開始想到動態規劃每個數字，後來發現對數字的存儲上很大問題，最多要存放10^6位數字。

後來換了思路，使用貪心的想法，從高位開始每次輸出最優數字。

/*************************************************************************
	> File Name: BB.cpp
	> Author: BSlin
	> Mail:  
	> Created Time: 2013年10月04日 星期五 19時16分55秒
 ************************************************************************/

#include <iostream>
#include <cstdio>
#include <cstring>
#include <string>
#include <cstdlib>
#include <cmath>
#include <algorithm>
#include <iterator>
#include <vector>
#include <map>
#include <set>
#include <stack>
#include <queue>
#define MP make_pair
#define INF (1<<30)
#define PI acos(-1.0)
#define esp 1e-8
const int dx[4]={0,0,0,0};
using namespace std;
#define read freopen("in.txt","r",stdin)
#define write freopen("out.txt","w",stdout)
#if defined (_WIN32) || defined (__WIN32) || defined (WIN32) || defined (__WIN32__)
#define LL __int64
#define LLS "%" "I" "6" "4" "d"
#else
#define LL long long
#define LLS "%" "l" "l" "d"
#endif



#define MAX 100010

int a[10];

int main(int argc, char** argv) {
    //read;
    int value,min,cnt;
    scanf("%d",&value);
    min = MAX;
    for(int i=1; i<=9; i++) {
        scanf("%d",&a[i]);
        if(min > a[i]) min = a[i];
    }
    if(value < min) {
        printf("-1\n");
        return 0;
    }
    cnt = value / min;
    for(int i=cnt-1; i>=0; i--) {
        for(int j=9; j>=1; j--) {
            if(value >= a[j] && (value - a[j]) / min >= i) { //注意：-1/2==0；value >= a[j]；
                printf("%d",j);
                value -= a[j];
                break;
            }
        }
    }
    printf("\n");
    return 0;
}