课程练习一-Problem Q

Problem Description

FJ is surveying his herd to find the most average cow. He wants to know how much milk this 'median' cow gives: half of the cows give as much or more than the median; half give as much or less. 

Given an odd number of cows N (1 <= N < 10,000) and their milk output (1..1,000,000), find the median amount of milk given such that at least half the cows give the same amount of milk or more and at least half give the same or less.

 

Input

* Line 1: A single integer N <br> <br>* Lines 2..N+1: Each line contains a single integer that is the milk output of one cow.

 

Output

* Line 1: A single integer that is the median milk output.

 

Sample Input

5 2 4 1 3 5

 

Sample Output

3

 

题意： 就是求一串数中中间大小的数

思路：将数存到数组中，排下序，取数组下标中间的数就是了。

代码：

#include<iostream>
#include<string.h>
#include<algorithm>
using namespace std;
int main()
{
int N;
cin>>N;
int a[10001];
memset(a,0,sizeof(a));
for(int i=0;i<N;i++)
{
cin>>a[i];
}
sort(a,a+N);
int m=(N)/2;
cout<<a[m]<<endl;
system("pause");
return 0;
}