HDU6308 Time Zone

Time Zone

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 895    Accepted Submission(s): 296

 

Problem Description

Chiaki often participates in international competitive programming contests. The time zone becomes a big problem.
Given a time in Beijing time (UTC +8), Chiaki would like to know the time in another time zone s.

 

 

Input

There are multiple test cases. The first line of input contains an integer T (1≤T≤106), indicating the number of test cases. For each test case:
The first line contains two integers a, b (0≤a≤23,0≤b≤59) and a string s in the format of "UTC+X'', "UTC-X'', "UTC+X.Y'', or "UTC-X.Y'' (0≤X,X.Y≤14,0≤Y≤9).

 

 

Output

For each test, output the time in the format of hh:mm (24-hour clock).

 

 

Sample Input

3 11 11 UTC+8 11 12 UTC+9 11 23 UTC+0

 

 

Sample Output

11:11 12:12 03:23

 題意：

這就是說給你一個時間HH：MM表示，然後讓你一北京衛時間時區，給你一個新時區，讓你計算新時區的時間，就是一道模擬題，注意一下正負14時區，正負0時區，還有就是，雖然是28時區，但是用的是24小時制，也就是在24時是0時。

算法：

純模擬，就是注意一些細節情況就行了。也不是太難的模擬題。

代碼：

#include<iostream>
#include<cstdio>
#include<string.h>
using namespace std;

int main()
{
    int T;
    scanf("%d",&T);
    while(T--)
    {
        int h,m;
        int x = 0,y = 0;
        char s[10] = {0};
        memset(s,'0',sizeof(s));
        scanf("%d%d%s",&h,&m,s);
        if(s[4] == '1')
        {
            x += s[4]-'0';
            if('0' <= s[5] && s[5] <= '9')
            {
                x *= 10;
                x += s[5]-'0';
                y = s[7]-'0';
            }
            else
            {
                y = s[6]-'0';
            }
        }
        else
        {
            x = s[4]-'0';
            y = s[6]-'0';
        }
        if(s[3] == '-')
        {
            x = 10+(14-x);
        }
        if(x != 8)
        {
            if(x > 8)
            {
                h += x-8;
                if(y != 0)
                {
                    if(s[3] == '-')
                    {
                        m -= 6*y;
                        if(m < 0)
                        {
                            m += 60;
                            h --;
                        }
                    }
                    else
                    {
                        m += 6*y;
                        if(m > 59)
                        {
                            m -= 60;
                            h ++;
                        }
                    }
                }
                if(h >= 24) h -= 24;
            }
            else
            {
                h -= 8-x;
                if(y != 0)
                {
                    m += 6*y;
                    if(m > 59)
                    {
                        m -= 60;
                        h ++;
                    }
                }
                if(h < 0) h += 24;
            }
            printf("%02d:%02d\n",h,m);
        }
        else
        {
            if(y != 0)
            {
                m += 6*y;
                if(m > 59)
                {
                    m -= 60;
                    h ++;
                }
            }
            if(h >= 24) h -= 24;
            printf("%02d:%02d\n",h,m);
        }
    }
    return 0;
}

這是我AC了的代碼，開始被卡住了，14時區每分好...............選擇咬舌自盡.。。。。。

菜得不一樣，菜出新高度。