MIT18.06学习笔记 - Lecture 7: Solving Ax=0: pivot variables and special solutions

这个系列文章是我重温Gilbert老爷子的线性代数在线课程的学习笔记。
Course Name:MIT 18.06 Linear Algebra
Text Book: Introduction to Linear Algebra
章节内容: 3.2-3.3


课程提纲
1. Nullspace of A and solutions
2. The Rank and Row Reduced Form

课程重点

Nullspace of A and solutions

Nullspace N(A) consists of all solutions to Ax=0 , all combinations of the special solutions.

If A is invertible, x=0 is the only solution, otherwise there are nonzero solutions.

Computing the Nullspace
Two steps to solve Ax=0 , A is rectangular: elimination to Echelon Matrices and combinations of special solutions

The Rank and Row Reduced Form

The rank of A is the number of pivots. This number is r .
The matrices A and U and R have r independent rows (the pivot rows) and r independent columns (the pivot columns).
The rank r is the dimension of the column space as well as the row space.


Ax=uvTx=u(xTx)=0 , so xTx=0 nullspace (plane) perpendicular to row space (line):

Row Reduced Form

The nullspace matrix N contains the three special solutions in it columns, so AN= zero matrix:

AX=0 has r pivots and nr free variables: n columns minus r pivot columns. The nullspace matrix N contains the nr special solutions.
The special solutions are easy for Rx=0 . Suppose that the first r columns are the pivot columns:



發表評論
所有評論
還沒有人評論,想成為第一個評論的人麼? 請在上方評論欄輸入並且點擊發布.
相關文章