#10052. 「一本通 2.3 練習 1」Immediate Decodability

#10052. 「一本通 2.3 練習 1」Immediate Decodability

大意：給一些數字串，問是否有數字串是另一數字串的前綴。  字典樹板子

#include <bits/stdc++.h>
using namespace std;
const int maxn = 500;
int tre[maxn][11],sz;
struct node{
    char A[11];
    int len;
}mp[maxn];
int n,m;
bool cmp(node a,node b){
    return a.len>b.len;
}
bool solve(int t){
    int len = mp[t].len,now=0;
    for(int i=0;i<len;++i){
        int tem = mp[t].A[i] - '0';
        if(i==len-1&&tre[now][tem]) return 0;
        if(!tre[now][tem]) tre[now][tem] = ++sz;
        now = tre[now][tem];
    }
    return 1;
}
int main(){
    int _=1;
    while(~scanf("%s",mp[0].A)){
        mp[0].len = strlen(mp[0].A);
        sz = 0;
        memset(tre,0,sizeof(tre));
        for(n = 1;;++n){
            scanf("%s",mp[n].A);
            int t = strlen(mp[n].A);
            if(t==1&&mp[n].A[0]=='9') break;
            mp[n].len = t;
        }
        sort(mp,mp+n,cmp);
        int flag = 0;
        for(int i=0;i<n;++i){
            if(!solve(i)){
                flag = 1;
                break;
            }
        }
        if(flag) printf("Set %d is not immediately decodable\n",_++);
        else printf("Set %d is immediately decodable\n",_++);
    }
    return 0;
}