1115 Counting Nodes in a BST(30 分)
A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:
- The left subtree of a node contains only nodes with keys less than or equal to the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
Insert a sequence of numbers into an initially empty binary search tree. Then you are supposed to count the total number of nodes in the lowest 2 levels of the resulting tree.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (≤1000) which is the size of the input sequence. Then given in the next line are the N integers in [−10001000] which are supposed to be inserted into an initially empty binary search tree.
Output Specification:
For each case, print in one line the numbers of nodes in the lowest 2 levels of the resulting tree in the format:
n1 + n2 = n
where n1
is the number of nodes in the lowest level, n2
is that of the level above, and n
is the sum.
Sample Input:
9
25 30 42 16 20 20 35 -5 28
Sample Output:
2 + 4 = 6
令人懷念的指針二叉樹。。。
code
#pragma warning(disable:4996)
#include <iostream>
#include <string>
#include <vector>
#include <cmath>
#include <set>
#include <stdio.h>
using namespace std;
class tree {
public:
int val;
tree *left = NULL, *right=NULL;
};
void insert(tree*& head, int x) {
if (head == NULL) {
head = new tree;
head->val = x;
return;
}
if (x > head->val) insert(head->right, x);
else insert(head->left, x);
}
int levelnum[1000];
void runer(tree* head, int level) {
if (head == NULL) return;
levelnum[level]++;
runer(head->left, level + 1);
runer(head->right, level + 1);
}
int main() {
int n, x;
cin >> n;
tree* p = NULL;
for (int i = 0; i < n; ++i) {
cin >> x;
insert(p, x);
}
runer(p,1);
for (int i = 99; i >= 0; --i) {
if (levelnum[i] != 0) {
cout << levelnum[i] << " + " << levelnum[i - 1] <<" = "<<levelnum[i]+levelnum[i-1] << endl;
break;
}
}
system("pause");
return 0;
}