hdu1907

John

Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)
Total Submission(s): 2659    Accepted Submission(s): 1462

Problem Description

Little John is playing very funny game with his younger brother. There is one big box filled with M&Ms of different colors. At first John has to eat several M&Ms of the same color. Then his opponent has to make a turn. And so on. Please note that each player has to eat at least one M&M during his turn. If John (or his brother) will eat the last M&M from the box he will be considered as a looser and he will have to buy a new candy box.

Both of players are using optimal game strategy. John starts first always. You will be given information about M&Ms and your task is to determine a winner of such a beautiful game.

 

Input

The first line of input will contain a single integer T – the number of test cases. Next T pairs of lines will describe tests in a following format. The first line of each test will contain an integer N – the amount of different M&M colors in a box. Next line will contain N integers Ai, separated by spaces – amount of M&Ms of i-th color.

Constraints:
1 <= T <= 474,
1 <= N <= 47,
1 <= Ai <= 4747

 

Output

Output T lines each of them containing information about game winner. Print “John” if John will win the game or “Brother” in other case.

 

Sample Input

2 3 3 5 1 1 1

規定吃完最後一顆的就輸了，anti_sg，我也不是很懂，就是當所有堆都是1的時候特判，然後有一堆大於1的時候就按照nim遊戲來做

博弈實在弱爆了！被博弈各種爆菊！

#include<cstdio>
#include<vector>
#include<utility>
#include<cstring>
#include<iostream>
#include<algorithm>
#define LL long long
#define MM 100010
using namespace std;

int n;
int main() {
    int T;
    //freopen("D:\\o.txt", "r", stdin);
    scanf("%d", &T);
    while (T--)
    {
        int sum = 0, num = 0;
        scanf("%d", &n);
        for (int i = 1; i <= n; i++)
        {
            int x;
            scanf("%d", &x);
            if (x > 1)num++;
            sum ^= x;
        }
        if (num == 0)
        {
            if (n % 2 == 1)puts("Brother");
            else puts("John");
        }
        else
        {
            if (sum != 0)puts("John");
            else puts("Brother");
        }
    }
    return 0;
}